**Get Sketch The Region Enclosed By The Given Curves. Y = Sec2(X), Y = 8 Cos(X), −Π/3 ≤ X ≤ Π/3
Background**. Sketch the region enclosed by the given decide whether to integrate with respect to x or y. The curves enclose about 10 unit squares, so that matches the above result.

Y = sec2x, y = 8 cos x, −π/3 ≤ x ≤ π/3. We can extend the notion of the area under a curve and consider the area of the region between two curves. I sort of get that the x axis represents 'cos' and the y axis represents 'sin', but what about tan?

### The curves enclose about 10 unit squares, so that matches the above result.

2 (a) (i) sketch the graph of y = x cos x, for 0 ≤ x ≤ 2 making clear the approximate positions of the 2 (b) solve the equation 2 cos x + sin x = 2 for x in the interval 0 ≤ x ≤ π , giving your answers exactly. We welcome your feedback, comments and questions about this site or page. Cos(x) is above sin(2x) from 0 to pi/6. This problem has been solved!